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0.03x^2+80x+165=0
a = 0.03; b = 80; c = +165;
Δ = b2-4ac
Δ = 802-4·0.03·165
Δ = 6380.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-\sqrt{6380.2}}{2*0.03}=\frac{-80-\sqrt{6380.2}}{0.06} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+\sqrt{6380.2}}{2*0.03}=\frac{-80+\sqrt{6380.2}}{0.06} $
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